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Saturday, 31 October

JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 September 2020, Shift 1, Maths Q54

Question 54 of 75 in this shift, Maths question 4 of 25.

If the minimum and the maximum values of the function f:[π4,π2]→Rf:\left[\frac{\pi}{4},\frac{\pi}{2}\right]\to\mathbf{R}, defined by f(θ)=∣−sin⁡2θ−1−sin⁡2θ1−cos⁡2θ−1−cos⁡2θ11210−2∣f(\theta)=\begin{vmatrix}-\sin^2\theta & -1-\sin^2\theta & 1\\ -\cos^2\theta & -1-\cos^2\theta & 1\\ 12 & 10 & -2\end{vmatrix} are m and M respectively, then the ordered pair (m, M) is equal to :
  1. (1)(−4,4)(-4,4)
  2. (2)(0,22)(0,2\sqrt{2})
  3. (3)(−4,0)(-4,0)Official answer
  4. (4)(0,4)(0,4)

Official answer

Option 3

NTA final key (Sep 2020).

Chapter
Determinants
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.