Learn

Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 5 September 2020, Shift 1, Physics Q5

Question 5 of 75 in this shift, Physics question 5 of 25.

The value of the acceleration due to gravity is g1g_1 at a height h=R2h = \frac{R}{2} (R = radius of the earth) from the surface of the earth. It is again equal to g1g_1 at a depth d below the surface of the earth. The ratio (dR)\left(\frac{d}{R}\right) equals :
  1. (1)13\frac{1}{3}
  2. (2)49\frac{4}{9}
  3. (3)59\frac{5}{9}Official answer
  4. (4)79\frac{7}{9}

Official answer

Option 3

NTA final key (Sep 2020).

Chapter
Gravitation
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.