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Saturday, 31 October

JEE Main 2020 · ChemistryNumerical answerNumerical valueHardMulti-step

JEE Main 5 September 2020, Shift 1, Chemistry Q48

Question 48 of 75 in this shift, Chemistry question 23 of 25.

A soft drink was bottled with a partial pressure of CO2\mathrm{CO_2} of 3 bar over the liquid at room temperature. The partial pressure of CO2\mathrm{CO_2} over the solution approaches a value of 30 bar when 44 g of CO2\mathrm{CO_2} is dissolved in 1 kg of water at room temperature. The approximate pH of the soft drink is __________×10−1\times 10^{-1}. (First dissociation constant of H2CO3=4.0×10−7\mathrm{H_2CO_3} = 4.0\times10^{-7} ; log⁡2=0.3\log 2 = 0.3; density of the soft drink =1 g mL−1= 1\ \mathrm{g\ mL^{-1}})

Official answer

37.00

NTA final key (Sep 2020).

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