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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 September 2020, Shift 1, Physics Q16

Question 16 of 75 in this shift, Physics question 16 of 25.

An electron is constrained to move along the yy-axis with a speed of 0.1 c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is E⃗=30 j^ sin⁡(1.5×107t−5×10−2x)\vec{E} = 30\,\hat{j}\,\sin(1.5\times10^7 t - 5\times10^{-2}x) V/m. The maximum magnetic force experienced by the electron will be : (given c = 3×1083\times10^8 ms−1^{-1} and electron charge = 1.6×10−191.6\times10^{-19}C)
  1. (1)2.4×10−182.4\times10^{-18} N
  2. (2)4.8×10−194.8\times10^{-19} NOfficial answer
  3. (3)3.2×10−183.2\times10^{-18} N
  4. (4)1.6×10−191.6\times10^{-19} N

Official answer

Option 2

NTA final key (Sep 2020).

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.