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Saturday, 31 October

JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 4 September 2020, Shift 2, Maths Q63

Question 63 of 75 in this shift, Maths question 13 of 25.

The solution of the differential equation dydx−y+3xlog⁡e(y+3x)+3=0\frac{dy}{dx} - \frac{y+3x}{\log_e (y+3x)} + 3 = 0 is : (where C is a constant of integration.)
  1. (1)x−log⁡e(y+3x)=Cx - \log_e(y+3x) = C
  2. (2)x−2log⁡e(y+3x)=Cx - 2\log_e(y+3x) = C
  3. (3)x−12(log⁡e(y+3x))2=Cx - \frac{1}{2}(\log_e(y+3x))^2 = COfficial answer
  4. (4)y+3x−12(log⁡ex)2=Cy + 3x - \frac{1}{2}(\log_e x)^2 = C

Official answer

Option 3

NTA final key (Sep 2020).