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Saturday, 31 October

JEE Main 2020 · ChemistryMultiple choiceSingle correctMediumMulti-step

JEE Main 4 September 2020, Shift 2, Chemistry Q27

Question 27 of 75 in this shift, Chemistry question 2 of 25.

250 mL of a waste solution obtained from the workshop of a goldsmith contains 0.1 M AgNO3\mathrm{AgNO_3} and 0.1 M AuCl. The solution was electrolyzed at 2 V by passing a current of 1 A for 15 minutes. The metal/metals electrodeposited will be : (EAg+/Ag0=0.80 V, EAu+/Au0=1.69 V)\left(E^0_{\mathrm{Ag^+/Ag}} = 0.80\ \mathrm{V},\ E^0_{\mathrm{Au^+/Au}} = 1.69\ \mathrm{V}\right)
  1. (1)only silver
  2. (2)silver and gold in equal mass proportion
  3. (3)silver and gold in proportion to their atomic weights
  4. (4)only goldOfficial answer

Official answer

Option 4

NTA final key (Sep 2020).

Chapter
Electrochemistry
Topic
Faraday's Laws of Electrolysis
Idea tested
Predicting Products

Same idea in other shifts

Asked 2× in all
  1. 7 Apr 2025, Shift 2 · Q56Given below are two statements : 1 M aqueous solutions of each of Cu(NO3)2\mathrm{Cu(NO_3)_2}, AgNO3\mathrm{AgNO_3}, Hg2(NO3)2\mathrm{Hg_2(NO_3)_2},…MediumTwo statements

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.