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Saturday, 31 October

JEE Main 2020 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 4 September 2020, Shift 2, Physics Q23

Question 23 of 75 in this shift, Physics question 23 of 25.

Four resistances 40 Ω\Omega, 60 Ω\Omega, 90 Ω\Omega and 110 Ω\Omega make the arms of a quadrilateral ABCD. Across AC is a battery of emf 40 V and internal resistance negligible. The potential difference across BD in V is __________.

The figure, in words

Diamond of four resistors with nodes A (left), B (top), C (right), D (bottom): 40 ohm on AB, 60 ohm on BC, 90 ohm on AD, 110 ohm on DC. A wire from A goes left and down, along the bottom (passing below D) and up to C; the bottom wire contains a battery marked 40 V, drawn below D.

Official answer

2.00

NTA final key (Sep 2020).

Chapter
Current Electricity
Topic
Wheatstone Bridge
Idea tested
Unbalanced Bridge Analysis

Same idea in other shifts

Asked 4× in all
  1. 15 Apr 2023, Shift 1 · Q60A network of four resistances is connected to 9 V battery, as shown in figure. The magnitude of voltage difference between the points A…MediumNumerical valueHas a figure
  2. 17 Mar 2021, Shift 2 · Q16The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15 Ω\Omega resistance is connected across…HardDiagram basedHas a figure
  3. 9 Jan 2020, Shift 1 · Q20In the given circuit diagram, a wire is joining points B and D. The current in this wire is :MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.