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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceDiagram basedEasyData or graph

JEE Main 4 September 2020, Shift 2, Physics Q17

Question 17 of 75 in this shift, Physics question 17 of 25.

In a photoelectric effect experiment, the graph of stopping potential V versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased :

The figure, in words

Graph with a vertical axis labelled V (arrowhead up) and a horizontal axis labelled 1/\lambda (arrowhead right). A straight line starts on the horizontal axis at a point to the right of the origin and rises to the upper right; an angle \theta is marked between the line and the horizontal axis.
  1. (1)Graph does not changeOfficial answer
  2. (2)Straight line shifts to left
  3. (3)Straight line shifts to right
  4. (4)Slope of the straight line get more steep

Official answer

Option 1

NTA final key (Sep 2020).

Chapter
Dual Nature of Radiation and Matter
Topic
Photoelectric Effect
Idea tested
Stopping Potential vs Frequency Graph

Same idea in other shifts

Asked 4× in all
  1. 6 Apr 2023, Shift 2 · Q44The work functions of Aluminium and Gold are 4.1 eV and and 5.1 eV respectively. The ratio of the slope of the stopping potential versus…EasySingle correct
  2. 10 Apr 2023, Shift 2 · Q45The variation of stopping potential (V0V_0) as a function of the frequency (ν\nu) of the incident light for a metal is shown in figure.…MediumDiagram basedHas a figure
  3. 4 Sep 2020, Shift 1 · Q20Given figure shows few data points in a photo electric effect experiment for a certain metal. The minimum energy for ejection of electron…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.