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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 4 September 2020, Shift 2, Physics Q11

Question 11 of 75 in this shift, Physics question 11 of 25.

A particle of charge q and mass m is subjected to an electric field E=E0(1−ax2)E = E_0(1 - ax^2) in the xx-direction, where a and E0E_0 are constants. Initially the particle was at rest at x=0x = 0. Other than the initial position the kinetic energy of the particle becomes zero when the distance of the particle from the origin is :
  1. (1)a
  2. (2)1a\sqrt{\frac{1}{a}}
  3. (3)2a\sqrt{\frac{2}{a}}
  4. (4)3a\sqrt{\frac{3}{a}}Official answer

Official answer

Option 4

NTA final key (Sep 2020).

Same idea in other shifts

Asked 2× in all
  1. 6 Apr 2026, Shift 1 · Q49A three coulomb charge moves from the point (0,−2,−5)(0,-2,-5) to the point (5,1,2)(5,1,2) in an electric field expressed as…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.