Learn

Saturday, 31 October

JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 4 September 2020, Shift 1, Maths Q66

Question 66 of 75 in this shift, Maths question 16 of 25.

Let P(3, 3) be a point on the hyperbola, x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1. If the normal to it at P intersects the xx-axis at (9, 0) and e is its eccentricity, then the ordered pair (a2,e2)(a^2, e^2) is equal to :
  1. (1)(92,2)\left(\frac{9}{2}, 2\right)
  2. (2)(9,3)(9, 3)
  3. (3)(32,2)\left(\frac{3}{2}, 2\right)
  4. (4)(92,3)\left(\frac{9}{2}, 3\right)Official answer

Official answer

Option 4

NTA final key (Sep 2020).