JEE Main 2020 · ChemistryMultiple choiceDiagram basedEasyData or graph
JEE Main 4 September 2020, Shift 1, Chemistry Q28
Question 28 of 75 in this shift, Chemistry question 3 of 25.
For the equilibrium , the variation of the rate of the forward (a) and reverse (b) reaction with time is given by :
The figure, in words
Four graphs of Rate of reaction (y-axis) against Time (x-axis), each with curves labelled a and b and a double-headed arrow labelled equilibrium. Stem prints 'A' followed by a stray tick before the equilibrium arrow.- (1)[figure: graph of Rate of reaction vs Time; curve a falls from a high value, curve b rises from zero, the two curves meet and merge into a single level line at the point marked equilibrium]Official answer
- (2)[figure: graph of Rate of reaction vs Time; curve a falls from a high value, curve b rises from zero, they cross, then a levels off below b and b levels off above a, marked equilibrium]
- (3)[figure: graph of Rate of reaction vs Time; curve a falls and curve b rises, both level off with a staying above b at the end, marked equilibrium (the two remain separated by a gap)]
- (4)[figure: graph of Rate of reaction vs Time; curve a falls then turns up again, curve b rises then turns down again, so the two curves move apart after the closest point, marked equilibrium]
Official answer
Option 1
NTA final key (Sep 2020).
- Chapter
- Equilibrium
- Topic
- Chemical Equilibrium
- Idea tested
- Rate-Time Graph Analysis