JEE Main 2020 (4 Sep, Shift 1) Physics Q18: Matter Waves

Question

Particle A of mass

m_A=\frac{m}{2}

moving along the

x

-axis with velocity

v_0

collides elastically with another particle B at rest having mass

m_B=\frac{m}{3}

. If both particles move along the

x

-axis after the collision, the change

\Delta\lambda

in de-Broglie wavlength of particle A, in terms of its de-Broglie wavelength (

\lambda_0

) before collision is :

Official answer

Option 4

NTA final key (Sep 2020).

Accepted Answer

Option 4: $\Delta\lambda=4\lambda_0$

Answer

$\Delta\lambda=\frac{3}{2}\lambda_0$

Answer

$\Delta\lambda=2\lambda_0$

Answer

$\Delta\lambda=\frac{5}{2}\lambda_0$

Answer

$\Delta\lambda=4\lambda_0$

JEE Main 4 September 2020, Shift 1, Physics Q18