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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceDiagram basedMediumCalculation

JEE Main 4 September 2020, Shift 1, Physics Q11

Question 11 of 75 in this shift, Physics question 11 of 25.

A two point charges 4q and −-q are fixed on the xx-axis at x=−d2x=-\frac{d}{2} and x=d2x=\frac{d}{2}, respectively. If a third point charge ‘q’ is taken from the origin to xx=d along the semicircle as shown in the figure, the energy of the charge will :

The figure, in words

A horizontal axis with two tick marks, labelled 4q (left of a vertical line through the origin) and −-q (right of the vertical line); a vertical line rises from the origin. A semicircular arc with arrowheads starts at the origin, goes up and over, and ends on the horizontal axis at a point to the right of the −-q tick.
  1. (1)decrease by q24πϵ0d\frac{q^2}{4\pi\epsilon_0 d}
  2. (2)increase by 3q24πϵ0d\frac{3q^2}{4\pi\epsilon_0 d}
  3. (3)decrease by 4q23πϵ0d\frac{4q^2}{3\pi\epsilon_0 d}Official answer
  4. (4)increase by 2q23πϵ0d\frac{2q^2}{3\pi\epsilon_0 d}

Official answer

Option 3

NTA final key (Sep 2020).