JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 September 2020, Shift 1, Maths Q62

Question 62 of 75 in this shift, Maths question 12 of 25.

Area (in sq. units) of the region outside

\frac{|x|}{2}+\frac{|y|}{3}=1

and inside the ellipse

\frac{x^{2}}{4}+\frac{y^{2}}{9}=1

is :

(1) $3(4-\pi)$
(2) $6(4-\pi)$
(3) $6(\pi-2)$ Official answer
(4) $3(\pi-2)$

Official answer

Option 3

NTA final key (Sep 2020).

Chapter: Application of Integrals
Topic: Area Under Curves
Idea tested: Area of Ellipse and Sectors

Same topic in other shifts

All Area Under Curves questions

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4 Apr 2026, Shift 2 · Q18The area of the region bounded by the curves $x+3y^2=0$ and $x+4y^2=1$ is equal to:EasySingle correct
5 Apr 2026, Shift 1 · Q16The area of the region $R = \{(x, y) : xy \leq 27,\ 1 \leq y \leq x^2\}$ is equal to:MediumSingle correct
5 Apr 2026, Shift 2 · Q24Let $f:\mathbf{R}\to\mathbf{R}$ be a function such that $f(x)+3f\left(\frac{\pi}{2}-x\right)=\sin x$ , $x \in \mathbf{R}$ . Let the maximum…HardNumerical value
6 Apr 2026, Shift 1 · Q19The area of the region $\{(x,y): 0\le y\le 6-x,\ y^2\ge 4x-3,\ x\ge 0\}$ is:MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.