JEE Main 2020 (2 Sep, Shift 1) Maths Q59: If a function…

Question

If a function $f(x)$ defined by
$f(x)=\begin{cases} ae^{x}+be^{-x}, & -1\le x<1 \ cx^{2}, & 1\le x\le 3 \ ax^{2}+2cx, & 3<x\le 4 \end{cases}$
be continuous for some $a, b, c\in\mathbf{R}$ and $f'(0)+f'(2)=e$, then the value of $a$ is :

Accepted Answer

Option 1: $\frac{e}{e^{2}-3e+13}$

Answer

$\frac{e}{e^{2}-3e+13}$

Answer

$\frac{e}{e^{2}+3e+13}$

Answer

$\frac{e}{e^{2}-3e-13}$

Answer

$\frac{1}{e^{2}-3e+13}$

JEE Main 2 September 2020, Shift 1, Maths Q59

Same idea in other shifts