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Friday, 9 October

JEE Main 2020 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 2 September 2020, Shift 1, Maths Q56

Question 56 of 75 in this shift, Maths question 6 of 25.

Let α>0\alpha>0, β>0\beta>0 be such that α3+β2=4\alpha^{3}+\beta^{2}=4. If the maximum value of the term independent of xx in the binomial expansion of (αx19+βx−16)10\left(\alpha x^{\frac{1}{9}}+\beta x^{-\frac{1}{6}}\right)^{10} is 10k10k, then kk is equal to :
  1. (1)84
  2. (2)176
  3. (3)336Official answer
  4. (4)352

Official answer

Option 3

NTA final key (Sep 2020).

Chapter
Binomial Theorem
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.