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Friday, 9 October

JEE Main 2020 · ChemistryMultiple choiceDiagram basedHardMulti-step

JEE Main 2 September 2020, Shift 1, Chemistry Q43

Question 43 of 75 in this shift, Chemistry question 18 of 25.

The major aromatic product C in the following reaction sequence will be : 2-methyl-2H-chromene (benzene ring fused to a pyran ring with O, a CH(CH3) next to O and a CH=CH in the ring) →ΔHBr (excess)\xrightarrow[\Delta]{\mathrm{HBr\ (excess)}} A →(ii) H+(i) KOH (Alc.)\xrightarrow[\text{(ii) }\mathrm{H^+}]{\text{(i) KOH (Alc.)}} B →O3, Zn/H3O+\xrightarrow{\mathrm{O_3},\ \mathrm{Zn/H_3O^+}} C

The figure, in words

Starting material drawn as a bicyclic 2-methyl-2H-chromene (benzene fused to a six-membered ring containing O, with a methyl-bearing carbon next to O and a C=C); reaction arrows: HBr (excess), heat gives A; (i) KOH (Alc.), (ii) H+ gives B; O3, Zn/H3O+ gives C.
  1. (1)[figure: benzene ring with Br and CHO on adjacent (ortho) carbons]
  2. (2)[figure: benzene ring with Br and CH2CO2H\mathrm{CH_2CO_2H} on adjacent (ortho) carbons]
  3. (3)[figure: benzene ring with OH and CHO on adjacent (ortho) carbons]Official answer
  4. (4)[figure: benzene ring with OH and CH2CO2H\mathrm{CH_2CO_2H} on adjacent (ortho) carbons]

Official answer

Option 3

NTA final key (Sep 2020).

Topic
Ethers