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Friday, 9 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 2 September 2020, Shift 1, Physics Q19

Question 19 of 75 in this shift, Physics question 19 of 25.

An amplitude modulated wave is represented by the expression vm=5(1+0.6cos⁡6280t)sin⁡(211×104 t)v_m=5(1+0.6\cos 6280t)\sin(211\times10^{4}\,t) volts The minimum and maximum amplitudes of the amplitude modulated wave are, respectively :
  1. (1)52\frac{5}{2} V, 8 VOfficial answer
  2. (2)3 V, 5 V
  3. (3)32\frac{3}{2} V, 5 V
  4. (4)5 V, 8 VOfficial answer

Official answer

Options 1 and 4

NTA final key (Sep 2020): multiple options accepted. Either option scored full marks.

Chapter
Communication Systems
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.