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Friday, 9 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 2 September 2020, Shift 1, Physics Q17

Question 17 of 75 in this shift, Physics question 17 of 25.

Interference fringes are observed on a screen by illuminating two thin slits 1 mm apart with a light source (λ=632.8\lambda=632.8 nm). The distance between the screen and the slits is 100 cm. If a bright fringe is observed on a screen at a distance of 1.27 mm from the central bright fringe, then the path difference between the waves, which are reaching this point from the slits is close to :
  1. (1)1.27 μm1.27\ \mu\mathrm{m}Official answer
  2. (2)2.872.87 nm
  3. (3)2 nm
  4. (4)2.05 μm2.05\ \mu\mathrm{m}

Official answer

Option 1

NTA final key (Sep 2020).