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JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumConceptual

JEE Main 2 September 2020, Shift 1, Physics Q1

Question 1 of 75 in this shift, Physics question 1 of 25.

If speed

V

, area

A

and force

F

are chosen as fundamental units, then the dimension of Young's modulus will be :

(1) $FA^{2}V^{-2}$
(2) $FA^{2}V^{-3}$
(3) $FA^{-1}V^{0}$ Official answer
(4) $FA^{2}V^{-1}$

Official answer

Option 3

NTA final key (Sep 2020).

Chapter: Units and Measurements
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.