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Friday, 9 October

JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 January 2020, Shift 2, Maths Q62

Question 62 of 75 in this shift, Maths question 12 of 25, Section A.

If ∫dθcos⁡2θ(tan⁡2θ+sec⁡2θ)=λtan⁡θ+2log⁡e∣f(θ)∣+C\int\frac{d\theta}{\cos^2\theta(\tan2\theta+\sec2\theta)}=\lambda\tan\theta+2\log_e|f(\theta)|+C where CC is a constant of integration, then the ordered pair (λ,f(θ))(\lambda,f(\theta)) is equal to :
  1. (1)(−1,1+tan⁡θ)(-1,1+\tan\theta)Official answer
  2. (2)(1,1−tan⁡θ)(1,1-\tan\theta)
  3. (3)(−1,1−tan⁡θ)(-1,1-\tan\theta)
  4. (4)(1,1+tan⁡θ)(1,1+\tan\theta)

Official answer

Option 1

NTA final key (Jan 2020).

Chapter
Integrals

Same idea in other shifts

Asked 2× in all
  1. 5 Apr 2026, Shift 1 · Q20The value of the integral ∫π/6π/3(4−cosec⁡2xcos⁡4x)dx\int_{\pi/6}^{\pi/3}\left(\frac{4 - \operatorname{cosec}^2 x}{\cos^4 x}\right)dx is:MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.