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JEE Main 2020 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 9 January 2020, Shift 2, Maths Q56

Question 56 of 75 in this shift, Maths question 6 of 25, Section A.

In the expansion of

\left(\frac{x}{\cos\theta}+\frac{1}{x\sin\theta}\right)^{16}

, if

l_1

is the least value of the term independent of

x

when

\frac{\pi}{8}\le\theta\le\frac{\pi}{4}

and

l_2

is the least value of the term independent of

x

when

\frac{\pi}{16}\le\theta\le\frac{\pi}{8}

, then the ratio

l_2:l_1

is equal to :

(1) $1:16$
(2) $1:8$
(3) $16:1$ Official answer
(4) $8:1$

Official answer

Option 3

NTA final key (Jan 2020).

Chapter: Binomial Theorem
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.