JEE Main 2020 (9 Jan, Shift 2) Physics Q4: Collisions

Question

A particle of mass

m

is projected with a speed

u

from the ground at an angle

\theta = \frac{\pi}{3}

w.r.t. horizontal (

x

-axis). When it has reached its maximum height, it collides completely inelastically with another particle of the same mass and velocity

u\,\hat{i}

. The horizontal distance covered by the combined mass before reaching the ground is :

Official answer

Option 1

NTA final key (Jan 2020).

Accepted Answer

Option 1: $\frac{3\sqrt{3}}{8}\frac{u^2}{g}$

Answer

$\frac{3\sqrt{3}}{8}\frac{u^2}{g}$

Answer

$\frac{5}{8}\frac{u^2}{g}$

Answer

$2\sqrt{2}\frac{u^2}{g}$

Answer

$\frac{3\sqrt{2}}{4}\frac{u^2}{g}$

JEE Main 9 January 2020, Shift 2, Physics Q4