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Friday, 9 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 9 January 2020, Shift 2, Physics Q12

Question 12 of 75 in this shift, Physics question 12 of 25, Section A.

Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown below at time t=0t=0. If the charge on capacitors A and B at time t=CRt=CR is QAQ_A and QBQ_B respectively, then (Here ee is the base of natural logarithm)

The figure, in words

Two circuits, each a charged capacitor (A, B) in series with a resistor R and a diode. In circuit A the diode is oriented so that it blocks discharge; in circuit B the diode is reversed (conducting), so the capacitor discharges through R.
  1. (1)QA=VC, QB=CVQ_A = VC,\ Q_B = CV
  2. (2)QA=CV2, QB=VCeQ_A = \frac{CV}{2},\ Q_B = \frac{VC}{e}
  3. (3)QA=VCe, QB=CV2Q_A = \frac{VC}{e},\ Q_B = \frac{CV}{2}
  4. (4)QA=VC, QB=VCeQ_A = VC,\ Q_B = \frac{VC}{e}Official answer

Official answer

Option 4

NTA final key (Jan 2020).