JEE Main 2020 (9 Jan, Shift 1) Maths Q62: Integrals

Question

The integral $\int\frac{\mathrm{d}x}{(x+4)^{8/7}(x-3)^{6/7}}$ is equal to :
(where C is a constant of integration)

Accepted Answer

Option 2: $\left(\frac{x-3}{x+4}\right)^{1/7}+\mathrm{C}$

Answer

$\frac{1}{2}\left(\frac{x-3}{x+4}\right)^{3/7}+\mathrm{C}$

Answer

$\left(\frac{x-3}{x+4}\right)^{1/7}+\mathrm{C}$

Answer

$-\left(\frac{x-3}{x+4}\right)^{-1/7}+\mathrm{C}$

Answer

$-\frac{1}{13}\left(\frac{x-3}{x+4}\right)^{-13/7}+\mathrm{C}$

JEE Main 9 January 2020, Shift 1, Maths Q62