JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 9 January 2020, Shift 1, Physics Q17

Question 17 of 75 in this shift, Physics question 17 of 25, Section A.

A particle moving with kinetic energy E has de Broglie wavelength

\lambda

. If energy

\Delta E

is added to its energy, the wavelength become

\lambda/2

. Value of

\Delta E

, is :

(1) $E$
(2) $2E$
(3) $3E$ Official answer
(4) $4E$

Official answer

Option 3

NTA final key (Jan 2020).

Chapter: Dual Nature of Radiation and Matter
Topic: Matter Waves
Idea tested: Wavelength from Kinetic Energy

Same idea in other shifts

Asked 7× in all

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15 Apr 2023, Shift 1 · Q45The de Broglie wavelength of an electron having kinetic energy E is $\lambda$ . If the kinetic energy of electron becomes $\frac{E}{4}$ ,…EasySingle correct
26 Aug 2021, Shift 2 · Q8The de-Broglie wavelength of a particle having kinetic energy E is $\lambda$ . How much extra energy must be given to this particle so that…MediumSingle correct
25 Jul 2021, Shift 1 · Q6What should be the order of arrangement of de-Broglie wavelength of electron ( $\lambda_e$ ), an $\alpha$ -particle ( $\lambda_\alpha$ ) and…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.