JEE Main 2020 (8 Jan, Shift 2) Chemistry Q44: Among the…

Question

Among the compounds A and B with molecular formula $\mathrm{C_9H_{18}O_3}$, A is having higher boiling point the B. The possible structures of A and B are :

Accepted Answer

Option 2: A = [figure: same as option 1 A: six-membered ring with three branches, each a single bend line ending in HO/OH]; B = [figure: six-membered ring with $\mathrm{H_3CO}$, $\mathrm{OCH_3}$ and $\mathrm{OCH_3}$ attached directly at alternate ring atoms]

Answer

A = [figure: six-membered ring with three branches at alternate ring atoms, each a single bend line ending in HO/OH]; B = [figure: six-membered ring with HO at one ring atom, OH at another, and a longer zigzag chain at the third ring atom ending in OH]

Answer

A = [figure: same as option 1 A: six-membered ring with three branches, each a single bend line ending in HO/OH]; B = [figure: six-membered ring with $\mathrm{H_3CO}$, $\mathrm{OCH_3}$ and $\mathrm{OCH_3}$ attached directly at alternate ring atoms]

Answer

A = [figure: six-membered ring with $\mathrm{H_3CO}$, $\mathrm{OCH_3}$ and $\mathrm{OCH_3}$ attached directly at alternate ring atoms]; B = [figure: six-membered ring with HO at one ring atom, OH at another, and a longer zigzag chain at the third ring atom ending in OH]

Answer

A = [figure: six-membered ring with $\mathrm{H_3CO}$, $\mathrm{OCH_3}$ and $\mathrm{OCH_3}$ attached directly at alternate ring atoms]; B = [figure: six-membered ring with three branches at alternate ring atoms, each a single bend line ending in HO/OH]

JEE Main 8 January 2020, Shift 2, Chemistry Q44

Same idea in other shifts