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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 8 January 2020, Shift 2, Physics Q15

Question 15 of 75 in this shift, Physics question 15 of 25, Section A.

A plane electromagnetic wave of frequency 25 GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic field is given by B⃗=5×10−8 j^ T\vec{B}=5\times10^{-8}\,\hat{j}\ \mathrm{T}. The corresponding electric field E⃗\vec{E} is (speed of light c=3×108 ms−1c=3\times10^{8}\ \mathrm{ms^{-1}})
  1. (1)15 i^ V/m15\,\hat{i}\ \mathrm{V/m}Official answer
  2. (2)−15 i^ V/m-15\,\hat{i}\ \mathrm{V/m}
  3. (3)1.66×10−16 i^ V/m1.66\times10^{-16}\,\hat{i}\ \mathrm{V/m}
  4. (4)−1.66×10−16 i^ V/m-1.66\times10^{-16}\,\hat{i}\ \mathrm{V/m}

Official answer

Option 1

NTA final key (Jan 2020).

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.