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JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 8 January 2020, Shift 1, Maths Q64

Question 64 of 75 in this shift, Maths question 14 of 25, Section A.

Let the line

y=mx

and the ellipse

2x^2+y^2=1

intersect at a point P in the first quadrant. If the normal to this ellipse at P meets the co-ordinate axes at

\left(-\frac{1}{3\sqrt{2}},0\right)

and

(0,\beta)

, then

\beta

is equal to :

(1) $\frac{\sqrt{2}}{3}$ Official answer
(2) $\frac{2}{3}$
(3) $\frac{2}{\sqrt{3}}$
(4) $\frac{2\sqrt{2}}{3}$

Official answer

Option 1

NTA final key (Jan 2020).

Chapter: Conic Sections
Topic: Normals to Conics
Idea tested: Ellipse Normal Point Form

Same idea in other shifts

Asked 2× in all

2 Apr 2017 (offline) · Q80The eccentricity of an ellipse whose centre is at the origin is $\frac{1}{2}$ . If one of its directrices is $x=-4$ , then the equation of…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.