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JEE Main 2017 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2017 (offline), Maths Q72

Question 72 of 90 in this shift, Maths question 12 of 30.

The normal to the curve

y(x-2)(x-3)=x+6

at the point where the curve intersects the

y

-axis passes through the point :

(1) $\left(\frac{1}{2},\frac{1}{2}\right)$ Official answer
(2) $\left(\frac{1}{2},-\frac{1}{3}\right)$
(3) $\left(\frac{1}{2},\frac{1}{3}\right)$
(4) $\left(-\frac{1}{2},-\frac{1}{2}\right)$

Official answer

Option 1

CBSE answer key (25/04/2017, used for result).

Chapter: Application of Derivatives
Topic: Tangents and Normals
Idea tested: Equation of Normal

Same idea in other shifts

Asked 2× in all

2 Sep 2020, Shift 1 · Q64Let P(h, k) be a point on the curve $y=x^{2}+7x+2$ , nearest to the line, $y=3x-3$ . Then the equation of the normal to the curve at P is :MediumSingle correct

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.