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Friday, 9 October

JEE Main 2017 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2017 (offline), Maths Q67

Question 67 of 90 in this shift, Maths question 7 of 30.

The value of (21C1−10C1)+(21C2−10C2)+(21C3−10C3)+(21C4−10C4)+…+(21C10−10C10)(^{21}C_1-{}^{10}C_1)+(^{21}C_2-{}^{10}C_2)+(^{21}C_3-{}^{10}C_3)+(^{21}C_4-{}^{10}C_4)+\ldots+(^{21}C_{10}-{}^{10}C_{10}) is :
  1. (1)221−2102^{21}-2^{10}
  2. (2)220−292^{20}-2^{9}
  3. (3)220−2102^{20}-2^{10}Official answer
  4. (4)221−2112^{21}-2^{11}

Official answer

Option 3

CBSE answer key (25/04/2017, used for result).