JEE Main 2017 · PhysicsMultiple choiceSingle correctHardMulti-step

JEE Main 2 April 2017 (offline), Physics Q5

Question 5 of 90 in this shift, Physics question 5 of 30.

The moment of inertia of a uniform cylinder of length

l

and radius

R

about its perpendicular bisector is I. What is the ratio

l/R

such that the moment of inertia is minimum ?

(1) $\sqrt{\frac{3}{2}}$ Official answer
(2) $\frac{\sqrt{3}}{2}$
(3) $1$
(4) $\frac{3}{\sqrt{2}}$

Official answer

Option 1

CBSE answer key (25/04/2017, used for result).

Chapter: System of Particles and Rotational Motion
Topic: Moment of Inertia
Idea tested: MOI of a Cylinder About Transverse Axis

Same topic in other shifts

All Moment of Inertia questions

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6 Apr 2026, Shift 1 · Q31A solid sphere of radius 4 cm and mass 5 kg is rotating (rotation axis is passing through the centre of the sphere) with an angular…MediumSingle correct
2 Apr 2025, Shift 1 · Q32Moment of inertia of a rod of mass 'M' and length 'L' about an axis passing through its center and normal to its length is ' $\alpha$ '. Now…MediumSingle correct
2 Apr 2025, Shift 2 · Q28The moment of inertia of a circular ring of mass $M$ and diameter $r$ about a tangential axis lying in the plane of the ring is :EasySingle correct
7 Apr 2025, Shift 1 · Q46A, B and C are disc, solid sphere and spherical shell respectively with same radii and masses. These masses are placed as shown in figure.…HardNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.