JEE Main 2017 · ChemistryMultiple choiceSingle correctEasyCalculation

JEE Main 2 April 2017 (offline), Chemistry Q38

Question 38 of 90 in this shift, Chemistry question 8 of 30.

The radius of the second Bohr orbit for hydrogen atom is : (Planck's Const.

h=6.6262\times10^{-34}

Js; mass of electron

=9.1091\times10^{-31}

kg; charge of electron

e=1.60210\times10^{-19}

C; permittivity of vacuum

\epsilon_0=8.854185\times10^{-12}\ \mathrm{kg^{-1}m^{-3}A^2}

)

(1)0.529 Å
(2)2.12 ÅOfficial answer
(3)1.65 Å
(4)4.76 Å

Official answer

Option 2

CBSE answer key (25/04/2017, used for result).

Chapter: Structure of Atom
Topic: Bohr's Atomic Theory
Idea tested: Bohr Radius Calculation

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Asked 5× in all

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Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.