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Friday, 9 October

JEE Main 2017 · PhysicsMultiple choiceSingle correctHardMulti-step

JEE Main 2 April 2017 (offline), Physics Q3

Question 3 of 90 in this shift, Physics question 3 of 30.

A body of mass m=10−2m=10^{-2} kg is moving in a medium and experiences a frictional force F=−kv2F=-kv^2. Its initial speed is v0=10 ms−1v_0=10\ \mathrm{ms^{-1}}. If, after 10 s, its energy is 18mv02\frac{1}{8}mv_0^2, the value of k will be :
  1. (1)10−3 kg m−110^{-3}\ \mathrm{kg\,m^{-1}}
  2. (2)10−3 kg s−110^{-3}\ \mathrm{kg\,s^{-1}}
  3. (3)10−4 kg m−110^{-4}\ \mathrm{kg\,m^{-1}}Official answer
  4. (4)10−1 kg m−1s−110^{-1}\ \mathrm{kg\,m^{-1}s^{-1}}

Official answer

Option 3

CBSE answer key (25/04/2017, used for result).

Chapter
Laws of Motion
Topic
Newton's Laws of Motion
Idea tested
Velocity-Dependent Force (Drag)

Same topic in other shifts

All Newton's Laws of Motion questions
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  6. 7 Apr 2025, Shift 2 · Q28An object with mass 500 g moves along xx-axis with speed v=4xv=4\sqrt{x} m/s. The force acting on the object is :MediumSingle correct

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.