JEE Main 2017 · PhysicsMultiple choiceSingle correctEasyRecall

JEE Main 2 April 2017 (offline), Physics Q27

Question 27 of 90 in this shift, Physics question 27 of 30.

In a common emitter amplifier circuit using an n-p-n transistor, the phase difference between the input and the output voltages will be :

(1) $45^\circ$
(2) $90^\circ$
(3) $135^\circ$
(4) $180^\circ$ Official answer

Official answer

Option 4

CBSE answer key (25/04/2017, used for result).

Chapter: Semiconductor Electronics: Materials, Devices and Simple Circuits
Topic: Transistors
Idea tested: CE Amplifier Phase Reversal

Same topic in other shifts

All Transistors questions

8 Apr 2023, Shift 2 · Q43For a given transistor amplifier circuit in CE configuration $V_{CC} = 1$ V, $R_C = 1$ k $\Omega$ , $R_b = 100$ k $\Omega$ and $\beta = 100$ .…EasySingle correctHas a figure
24 Jun 2022, Shift 1 · Q53A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base…EasyNumerical value
29 Jun 2022, Shift 1 · Q58A transistor is used in an amplifier circuit in common emitter mode. If the base current changes by 100 $\mu$ A, it brings a change of 10…EasyNumerical value
18 Mar 2021, Shift 1 · Q21An npn transistor operates as a common emitter amplifier with a power gain of $10^6$ . The input circuit resistance is 100 $\Omega$ and the…MediumNumerical value
6 Sep 2020, Shift 2 · Q25The output characteristics of a transistor is shown in the figure. When $V_{CE}$ is 10 V and $I_C = 4.0$ mA, then value of $\beta_{ac}$ is…MediumNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.