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JEE Main 2 April 2017 (offline), Physics Q23
Question 23 of 90 in this shift, Physics question 23 of 30.
In a Young's double slit experiment, slits are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide is :
- (1)1.56 mm
- (2)7.8 mmOfficial answer
- (3)9.75 mm
- (4)15.6 mm
Official answer
Option 2
CBSE answer key (25/04/2017, used for result).
- Chapter
- Wave Optics
- Topic
- Young's Double Slit
- Idea tested
- Coincidence of Polychromatic Fringes