Learn

Friday, 9 October

JEE Main 2017 · PhysicsMultiple choiceSingle correctMediumData or graph

JEE Main 2 April 2017 (offline), Physics Q20

Question 20 of 90 in this shift, Physics question 20 of 30.

In a coil of resistance 100 Ω100\ \Omega, a current is induced by changing the magnetic flux through it as shown in the figure. The magnitude of change in flux through the coil is :

The figure, in words

Graph of current (amp.) vs time: straight line falling from 10 A at t=0 to 0 at t=0.5 sec.
  1. (1)200 Wb
  2. (2)225 Wb
  3. (3)250 WbOfficial answer
  4. (4)275 Wb

Official answer

Option 3

CBSE answer key (25/04/2017, used for result).

Chapter
Electromagnetic Induction
Topic
Faraday's Law
Idea tested
Induced Charge Flow

Same idea in other shifts

Asked 3× in all
  1. 13 Apr 2023, Shift 2 · Q58An insulated copper wire of 100 turns is wrapped around a wooden cylindrical core of the cross-sectional area 24 cm224\ \mathrm{cm^2}. The two…EasyNumerical value
  2. 3 Aug 2021, Shift 2 · Q14Two concentric and coplanar circular coils have radius aa and b (≫a)b\ (\gg a) as shown in figure. Resistance of the inner coil is RR.…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.