System of Particles and Rotational Motion

Physics · Class 11

Lesson 6 of 13 · 7 min

Torque and angular momentum

NCERT §6.7

Ananya helps close the stall's wooden door at night. Pushed near the handle, it swings shut easily; pushed near the hinges, it barely moves; pushed along its own surface, towards the hinge, it does not turn at all. The turning effect depends on where and how you push.

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In short

Torque (moment of force) is the rotational analogue of force: τ = r × F, where r is the position of the point of application from the origin. A door turns most easily when pushed at right angles at its outer edge; a push on the hinge line does nothing.

Magnitude τ = rF sin θ = r⊥F = rF⊥, where r⊥ is the perpendicular distance of the line of action from the origin (the moment arm) and F⊥ the component of F perpendicular to r.

Torque is zero if F = 0, r = 0, or the line of action passes through the origin (θ = 0° or 180°). Its SI unit is N m and dimensions M L² T⁻², the same as work, but torque is a vector and work a scalar.

Angular momentum of a particle about a point: l = r × p, magnitude l = rp sin θ = r⊥p.

dl/dt = τ: the rate of change of angular momentum equals the torque, the rotational form of F = dp/dt.

For a system, L = Σrᵢ × pᵢ and dL/dt = τ_ext. Internal torques cancel provided the forces between particles are equal, opposite and along the line joining them.

If τ_ext = 0, L is constant: conservation of angular momentum, three scalar laws for Lₓ, L_y, L_z.

A particle moving with constant velocity has constant angular momentum about any point: r sin θ is the fixed distance of its straight path from the point, and the direction of l does not change.

A fast-spinning bicycle rim held by one string at one end of its axle does not fall; its angular momentum precesses about the string, turning about an axis perpendicular to both L and the torque.

Torque and angular momentum | System of Particles and Rotational Motion | Lumi Learn