Lesson 6 of 13 · 7 min
Torque and angular momentum
NCERT §6.7
Ananya helps close the stall's wooden door at night. Pushed near the handle, it swings shut easily; pushed near the hinges, it barely moves; pushed along its own surface, towards the hinge, it does not turn at all. The turning effect depends on where and how you push.
The lesson in notes
In short
Torque (moment of force) is the rotational analogue of force: τ = r × F, where r is the position of the point of application from the origin. A door turns most easily when pushed at right angles at its outer edge; a push on the hinge line does nothing.
Magnitude τ = rF sin θ = r⊥F = rF⊥, where r⊥ is the perpendicular distance of the line of action from the origin (the moment arm) and F⊥ the component of F perpendicular to r.
Torque is zero if F = 0, r = 0, or the line of action passes through the origin (θ = 0° or 180°). Its SI unit is N m and dimensions M L² T⁻², the same as work, but torque is a vector and work a scalar.
Angular momentum of a particle about a point: l = r × p, magnitude l = rp sin θ = r⊥p.
dl/dt = τ: the rate of change of angular momentum equals the torque, the rotational form of F = dp/dt.
For a system, L = Σrᵢ × pᵢ and dL/dt = τ_ext. Internal torques cancel provided the forces between particles are equal, opposite and along the line joining them.
If τ_ext = 0, L is constant: conservation of angular momentum, three scalar laws for Lₓ, L_y, L_z.
A particle moving with constant velocity has constant angular momentum about any point: r sin θ is the fixed distance of its straight path from the point, and the direction of l does not change.
A fast-spinning bicycle rim held by one string at one end of its axle does not fall; its angular momentum precesses about the string, turning about an axis perpendicular to both L and the torque.