System of Particles and Rotational Motion

Physics · Class 11

Lesson 10 of 13 · 6 min

Kinematics of rotation

NCERT §6.10

The pump motor that runs the mela's fountain starts up each evening. Its wheel goes from 1200 rpm to 3120 rpm in 16 seconds, speeding up steadily. How many turns does it make while it does so?

Loading the full lesson

The lesson in notes

In short

With the axis fixed, a single angle θ describes the whole body (one degree of freedom). It is read for any one particle, from a fixed reference line in that particle's plane of motion.

θ, ω = dθ/dt and α = dω/dt correspond to x, v and a in linear motion.

For constant α: ω = ω₀ + αt, θ = θ₀ + ω₀t + ½αt², and ω² = ω₀² + 2α(θ − θ₀), where θ₀ and ω₀ are the values at t = 0.

ω = ω₀ + αt follows by integrating dω/dt = α with ω = ω₀ at t = 0; integrating once more gives the θ equation.

Convert rpm to rad/s by multiplying by 2π/60. 1200 rpm = 40π rad/s and 3120 rpm = 104π rad/s.

A motor wheel going from 1200 rpm to 3120 rpm in 16 s at constant α: α = (104π − 40π)/16 = 4π rad/s². It turns through θ = 40π × 16 + ½ × 4π × 16² = 1152π rad, that is 576 revolutions.

Kinematics of rotation | System of Particles and Rotational Motion | Lumi Learn