Simulation · Physics · Class 12
Fields from Gauss's law
From the lesson Applications of Gauss's law in Electric Charges and Fields. Change the values and watch what happens.
Fields from Gauss's lawPhysics · Class 12
The idea behind it
NCERT §1.14
- Infinitely long straight wire with uniform λ: by symmetry the field is radial and depends only on r. A coaxial cylinder of length l gives E × 2πrl = λl/ε₀, so E = λ/(2πε₀r), falling as 1/r.
- Infinite plane sheet with uniform σ: the field is normal to the sheet on both sides. A box straddling the sheet gives 2EA = σA/ε₀, so E = σ/(2ε₀), the same at every distance from the sheet.
- For a large finite sheet, E = σ/(2ε₀) holds well in the middle region away from the edges; for a long finite wire, λ/(2πε₀r) holds near its middle.
- Uniformly charged thin spherical shell, outside (r > R): E = q/(4πε₀r²), as if the whole charge q = 4πR²σ were at the centre.
- Inside the shell (r < R): the Gaussian sphere encloses no charge, so E = 0 everywhere inside. Experiments confirming this confirm the 1/r² law.
- A solid sphere with uniform volume charge also has, outside it, the field of a point charge at its centre.
- In each case the field on the Gaussian surface comes from the whole distribution, even though only the enclosed part appears in the law; the answers rely on the symmetry of an infinite wire or sheet.