Lesson 10 of 11 · 11 min
Complement and De Morgan's laws
NCERT §1.10
Sports day needs volunteers to run the stalls. The teacher wants everyone who signed up for neither cricket nor football. There are two natural ways to find them, and they must agree.
The lesson in notes
In short
The complement of A with respect to U is A′ = {x : x ∈ U and x ∉ A} = U − A: everything in the universal set that is outside A. A′ is itself a subset of U, and it changes if U changes.
Complement laws: A ∪ A′ = U and A ∩ A′ = φ. Double complement: (A′)′ = A. Also φ′ = U and U′ = φ.
De Morgan's laws: (A ∪ B)′ = A′ ∩ B′ and (A ∩ B)′ = A′ ∪ B′. Taking the complement swaps ∪ and ∩ and puts a dash on each set.
Check with U = {1, …, 6}, A = {2, 3}, B = {3, 4, 5}: A ∪ B = {2, 3, 4, 5}, so (A ∪ B)′ = {1, 6}; A′ = {1, 4, 5, 6} and B′ = {1, 2, 6}, so A′ ∩ B′ = {1, 6} as well.
In a Venn diagram A′ is the part of the rectangle outside A's circle, and (A ∪ B)′ is the region outside both circles.
A useful rewrite that follows from the definitions: A − B = A ∩ B′, the part of A that is also outside B.