Probability

Maths · Class 11

Lesson 11 of 11 · 15 min

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Must-know facts

17 facts

  1. 1An event is any subset of the sample space; a sample space of n outcomes has 2ⁿ events.
  2. 2E occurs when the outcome ω ∈ E.
  3. 3Impossible event φ; sure event S.
  4. 4Simple event: one sample point; n outcomes give exactly n simple events. Compound event: more than one point.
  5. 5not A = A′ = S − A; A or B = A ∪ B; A and B = A ∩ B; A but not B = A − B = A ∩ B′.
  6. 6Mutually exclusive: A ∩ B = φ. Exhaustive: the union is S.
  7. 7Mutually exclusive and exhaustive: exactly one of the events occurs every time.
  8. 8Axioms: P(E) ≥ 0, P(S) = 1, P(E ∪ F) = P(E) + P(F) for disjoint E, F.
  9. 9P(φ) = 0 follows from the axioms.
  10. 10Valid assignment: every P(ωᵢ) in [0, 1] and the total is exactly 1.
  11. 11P(A) = sum of P(ωᵢ) over the outcomes in A.
  12. 12Equally likely outcomes: P(E) = n(E)/n(S).
  13. 13P(A ∪ B) = P(A) − P(A ∩ B) + P(B): the overlap is removed once.
  14. 14Three events: add the singles, remove the pairs, add back P(A ∩ B ∩ C).
  15. 15P(not A) = 1 − P(A).
  16. 16Only one of two: P(A) + P(B) − 2P(A ∩ B).
  17. 17NCERT results: Example 7 gives 0.87, 0.98, 0.11; Example 10 gives 1/7735, 9/1547, 46/7735; Example 12 gives 1/60 and 1/10.

Common traps

Where marks are lost

Treating the 11 possible sums of two dice as equally likely.

Use the 36 ordered pairs; a sum of 7 has 6 of them, a sum of 2 only 1.

Adding P(A) and P(B) for events that overlap.

Subtract P(A ∩ B); only disjoint events add directly.

Thinking mutually exclusive means exhaustive, or the other way round.

Exclusive: no overlap. Exhaustive: nothing left out of S. A set of events can be either, both or neither.

Accepting a probability table because every entry lies between 0 and 1.

The entries must also add to exactly 1.

Using m/n on a weighted die or unfair coin.

m/n needs equally likely outcomes; otherwise add the individual outcome probabilities.

Counting 'at least one' case by case and missing a case.

Find P(none) and subtract it from 1.

Writing P(neither A nor B) = 1 − P(A) − P(B) for overlapping events.

Neither = (A ∪ B)′, so it is 1 − P(A ∪ B), with the overlap subtracted first.

Using permutations for a committee or a hand of cards.

Order does not matter there; count with combinations ⁿCᵣ.

Taking HT and TH as one outcome when two coins are tossed.

They are different outcomes; S = {HH, HT, TH, TT} has four equally likely points.

Formulas

10 to know

Complement

A′ = S − A, P(A′) = 1 − P(A)

A and A′ are mutually exclusive and exhaustive.

Difference

A − B = A ∩ B′

The event 'A but not B'.

Axioms

P(E) ≥ 0, P(S) = 1, P(E ∪ F) = P(E) + P(F) if E ∩ F = φ

Hence P(φ) = 0.

Event from outcomes

P(A) = Σ P(ωᵢ), ωᵢ ∈ A

Each 0 ≤ P(ωᵢ) ≤ 1 and all P(ωᵢ) add to 1.

Equally likely outcomes

P(E) = n(E)/n(S)

Each outcome has probability 1/n(S).

Addition rule

P(A ∪ B) = P(A) − P(A ∩ B) + P(B)

Usually written P(A) + P(B) − P(A ∩ B); the overlap is removed once.

Mutually exclusive events

P(A ∪ B) = P(A) + P(B)

Because P(A ∩ B) = 0.

Three events

P(A ∪ B ∪ C) = S₁ − S₂ + S₃

S₁ = sum of P of singles, S₂ = sum of P of the three pairwise intersections, S₃ = P(A ∩ B ∩ C).

Neither A nor B

P(A′ ∩ B′) = 1 − P(A ∪ B)

De Morgan: A′ ∩ B′ = (A ∪ B)′.

Exactly one of A, B

P(A) + P(B) − 2 P(A ∩ B)

P(A ∩ B′) + P(A′ ∩ B).

Key terms

12 terms

Random experiment
An experiment with more than one possible outcome, where the outcome cannot be predicted in advance.
Sample space
The set S of all possible outcomes of a random experiment.
Event
Any subset of the sample space.
Impossible event
The empty set φ; no outcome makes it happen.
Sure event
The whole sample space S; every outcome makes it happen.
Simple event
An event with exactly one sample point, also called an elementary event.
Compound event
An event with more than one sample point.
Complementary event
The event 'not A', A′ = S − A, made of the outcomes outside A.
Mutually exclusive events
Events that cannot occur together; their intersection is φ.
Exhaustive events
Events whose union is S, so at least one of them always occurs.
Equally likely outcomes
Outcomes that all have the same probability.
Axiomatic approach
Defining probability as a function on events that obeys three rules: non-negative, P(S) = 1, and additive for disjoint events.
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