Electrochemistry

Chemistry · Class 12

Lesson 6 of 12 · 10 min

Molar conductivity and dilution

NCERT §2.4.2

Dilute the stall's KCl tenfold and its conductivity drops almost tenfold, yet each mole of salt now conducts more than before. How can both be true?

Loading the full lesson

The lesson in notes

In short

Molar conductivity Λm = κ/c. With κ in S m⁻¹ and c in mol m⁻³, Λm is in S m² mol⁻¹; with κ in S cm⁻¹, Λm (S cm² mol⁻¹) = κ × 1000/molarity. 1 S cm² mol⁻¹ = 10⁻⁴ S m² mol⁻¹, and 1 mol L⁻¹ = 1000 mol m⁻³.

Worked: a cell reads 100 Ω with 0.1 M KCl (κ = 1.29 S m⁻¹), so G* = 129 m⁻¹; with 0.02 M KCl it reads 520 Ω, so κ = 0.248 S m⁻¹ and Λm = 0.248/20 = 124 × 10⁻⁴ S m² mol⁻¹.

On dilution κ always falls, for strong and weak electrolytes alike, because fewer ions are left in each unit volume.

Λm rises on dilution. Λm is the conductance of the whole volume holding 1 mol of electrolyte, set between electrodes 1 unit apart; that volume grows faster than κ shrinks.

The limit of Λm as c → 0 is the limiting molar conductivity, Λ°m.

Strong electrolytes: Λm rises slowly and Λm = Λ°m − A c^½, a straight line against √c with intercept Λ°m and slope −A. A depends on the solvent, temperature and electrolyte type (NaCl 1-1, CaCl₂ 2-1, MgSO₄ 2-2), and is the same for all electrolytes of one type.

Worked (KCl): the Λm–√c line gives Λ°m = 150.0 S cm² mol⁻¹ and A = 87.46 S cm² mol⁻¹ (mol L⁻¹)^−½.

Weak electrolytes such as acetic acid: Λm stays low at ordinary concentrations and shoots up steeply near zero, because the degree of dissociation grows on dilution. The curve cannot be extrapolated to find Λ°m.

Watch a class

Prefer a video? Watch this

Conductivity cell and molar conductivity basics

Schoolchemistry · English · Lecture · Open on YouTube

Molar conductivity and dilution | Electrochemistry | Lumi Learn