Biomolecules

Chemistry · Class 12

Lesson 13 of 13 · 18 min

Chapter review

Watch a class

The whole chapter on YouTube

Full chapter revision following NCERT

NCERT Wallah · Hinglish · Whole chapter · Open on YouTube

Whole chapter in one sitting

Class 12 by Unacademy · Hinglish · Whole chapter · Open on YouTube

Loading the full lesson

Must-know facts

25 facts

  1. 1Carbohydrates: optically active polyhydroxy aldehydes or ketones, or compounds that hydrolyse to them. Cx(H₂O)y is not a test: acetic acid fits, rhamnose (C₆H₁₂O₅) does not.
  2. 2Mono (no hydrolysis; about 20 in nature), oligo (2–10 units), poly (many units; non-sugars).
  3. 3All monosaccharides, aldoses and ketoses, are reducing sugars.
  4. 4Glucose from starch: dilute H₂SO₄, 393 K, 2–3 atm. From sucrose: dilute HCl or H₂SO₄ in alcoholic solution, equal glucose and fructose.
  5. 5Glucose evidence: HI → n-hexane (straight chain); oxime + cyanohydrin (C=O); Br₂ water → gluconic acid (–CHO); pentaacetate (5 –OH); HNO₃ → saccharic acid (1° alcohol).
  6. 6D/L compares the lowest asymmetric carbon with glyceraldehyde; –OH on the right = D. It says nothing about (+) or (–): D-(–)-fructose.
  7. 7Glucose has no free –CHO: no Schiff's test, no NaHSO₃ adduct, pentaacetate ignores NH₂OH. C5–OH closes a six-membered pyranose ring.
  8. 8α-glucose m.p. 419 K (crystallised at 303 K); β-glucose m.p. 423 K (crystallised at 371 K). They are anomers, differing at C1.
  9. 9Fructose: ketohexose, keto at C2; C5–OH closes a five-membered furanose ring; D-(–).
  10. 10Sucrose: α-glucose C1 – β-fructose C2, non-reducing. Hydrolysis gives invert sugar because fructose (–92.4°) outweighs glucose (+52.5°).
  11. 11Maltose: α-glucose C1–C4 α-glucose, reducing. Lactose: β-galactose C1–C4 β-glucose, reducing.
  12. 12Starch = amylose (15–20%, soluble, unbranched, 200–1000 units, C1–C4) + amylopectin (80–85%, insoluble, branched C1–C6). Cellulose: β-glucose C1–C4, unbranched. Glycogen: like amylopectin, more branched.
  13. 13Proteins hydrolyse to α-amino acids only. Zwitter ion H₃N⁺–CHR–COO⁻ explains high m.p., water solubility and amphoteric behaviour.
  14. 14Glycine is the one optically inactive natural α-amino acid. Natural ones are mostly L.
  15. 15Ten essential amino acids: Val, Leu, Ile, Arg, Lys, Thr, Met, Phe, Trp, His.
  16. 16Peptide bond –CO–NH–; >10 amino acids = polypeptide; >100 residues and >10,000 u = protein; insulin has 51.
  17. 17Fibrous (keratin, myosin; insoluble) versus globular (insulin, albumins; soluble).
  18. 181° sequence; 2° α-helix (right-handed, intrachain H-bonds C=O···H–N) and β-pleated sheet (interchain H-bonds); 3° overall folding; 4° sub-unit arrangement.
  19. 19Denaturation (heat, pH) destroys 2° and 3° structure; 1° stays. Boiled egg, curdled milk.
  20. 20Enzymes: mostly globular proteins, specific, named with -ase; sucrose hydrolysis Ea 6.22 kJ mol⁻¹ with acid, 2.15 with sucrase.
  21. 21Fat-soluble A, D, E, K (stored); water-soluble B group and C (not stored, except B₁₂).
  22. 22A: xerophthalmia, night blindness. B₁: beri beri. B₂: cheilosis. B₆: convulsions. B₁₂: pernicious anaemia. C: scurvy. D: rickets, osteomalacia. E: fragile RBCs. K: longer clotting time.
  23. 23Nucleoside = base + sugar (at C1′); nucleotide = nucleoside + phosphate (at C5′); chain links 5′–3′ phosphodiester.
  24. 24DNA: 2-deoxyribose, A G C T, double helix, A–T and C–G. RNA: ribose, A G C U, single strand; m-, r-, t-RNA.
  25. 25Hormones: steroids (estrogens, androgens), polypeptides (insulin, endorphins), amino acid derivatives (epinephrine, norepinephrine; thyroxine from tyrosine).

Common traps

Where marks are lost

Calling any compound that fits Cx(H₂O)y a carbohydrate.

The definition is functional: polyhydroxy aldehyde or ketone. Acetic acid fits the formula and is not one; rhamnose, C₆H₁₂O₅, is one and does not fit.

Reading D as dextrorotatory.

D is configuration relative to glyceraldehyde; the sign is in the brackets. Fructose is D-(–), laevorotatory.

Deciding D or L from C2 of glucose.

Look only at the lowest asymmetric carbon, C5 in glucose, with –CHO at the top; its –OH on the right makes it D.

Saying glucose is non-reducing because its ring has no free –CHO.

The ring is in equilibrium with the open chain, and every monosaccharide reduces Tollens' and Fehling's reagents. What the ring explains is the failed Schiff's and NaHSO₃ tests.

Calling α- and β-glucose enantiomers or open-chain isomers.

They are anomers: cyclic forms differing only at C1, the anomeric carbon, with m.p. 419 K and 423 K.

Thinking sucrose is reducing because it contains glucose.

Its link joins glucose C1 to fructose C2, both reducing carbons, so none is free. Maltose and lactose keep a free C1 and are reducing.

Explaining invert sugar as sucrose becoming laevorotatory.

Sucrose is dextrorotatory; the hydrolysis mixture is laevorotatory because fructose's –92.4° outweighs glucose's +52.5°.

Separating starch and cellulose by their linkage positions.

Both use C1–C4 links in the main chain. Starch is made of α-glucose, cellulose of β-glucose; amylopectin also branches C1–C6.

Swapping the starch fractions.

Amylose: 15–20%, water-soluble, unbranched. Amylopectin: 80–85%, insoluble, branched.

Saying denaturation breaks peptide bonds.

Only 2° and 3° structure (mainly hydrogen bonds) is lost; the amino acid sequence, the 1° structure, is untouched.

Putting vitamin B₁₂ with vitamins that cannot be stored, or vitamin K with water-soluble ones.

B₁₂ is the stored exception among water-soluble vitamins; K is fat-soluble, with A, D and E.

Mixing up nucleoside and nucleotide, or pairing A with U in DNA.

Nucleoside = base + sugar; add phosphate at C5′ for a nucleotide. In DNA A pairs with T; uracil is found only in RNA.

Formulas

5 to know

Sucrose hydrolysis

C₁₂H₂₂O₁₁ + H₂O → C₆H₁₂O₆ (glucose) + C₆H₁₂O₆ (fructose)

Dilute HCl or H₂SO₄ in alcohol, or the enzyme sucrase; gives invert sugar.

Starch or cellulose to glucose

(C₆H₁₀O₅)n + nH₂O → nC₆H₁₂O₆

Dilute H₂SO₄, 393 K, 2–3 atm.

Maltase

C₁₂H₂₂O₁₁ (maltose) + H₂O → 2C₆H₁₂O₆ (glucose)

Enzyme named after its substrate.

Invert sugar rotation

equal masses: ½(+52.5°) + ½(–92.4°) = –19.95°

Glucose and fructose have the same molar mass, so equimolar = equal mass; the average is negative.

Peptide bonds in a chain

n amino acids → (n − 1) peptide bonds, (n − 1) H₂O lost

Tripeptide: 3 amino acids, 2 peptide bonds.

Key terms

15 terms

Carbohydrate
Optically active polyhydroxy aldehyde or ketone, or a compound that hydrolyses to one.
Reducing sugar
A sugar that reduces Fehling's solution and Tollens' reagent.
Aldose / ketose
Monosaccharide with an aldehyde / keto group.
Anomers
Cyclic forms of a sugar that differ only at the anomeric carbon (C1 in glucose).
Pyranose / furanose
Six-membered / five-membered sugar ring containing one oxygen.
Glycosidic linkage
Oxygen bridge between two sugar units, formed with loss of water.
Invert sugar
The laevorotatory glucose–fructose mixture from hydrolysing dextrorotatory sucrose.
Zwitter ion
Dipolar form of an amino acid, H₃N⁺–CHR–COO⁻, neutral overall.
Essential amino acid
One the body cannot make, so it must come from the diet.
Peptide bond
The amide link –CO–NH– between amino acids.
Denaturation
Loss of 2° and 3° structure and of activity on heating or pH change; 1° structure kept.
Enzyme
A biocatalyst, almost always a globular protein, specific to its reaction and substrate.
Nucleotide
Base + pentose sugar + phosphate (at C5′).
Complementary strands
DNA strands whose bases pair A with T and C with G.
Hormone
An intercellular messenger released by an endocrine gland into the blood.
Test yourself: 10 questionsExam-style questions on Biomolecules, with full solutions.Start
Chapter review | Biomolecules | Lumi Learn