Lesson 6 of 13 · 5 min
Ammonia derivatives and reduction
NCERT §8.4
To identify an unknown flavour sample, Tara adds 2,4-DNP reagent and an orange solid drops out at once. The chemist says she has just confirmed a C=O group.
The lesson in notes
In short
Ammonia and its derivatives, H₂N–Z, add to C=O in a reversible, acid-catalysed reaction. The intermediate loses water quickly to form >C=N–Z, which pulls the equilibrium towards product.
Table 8.2 (Z → reagent → product): –H, ammonia → imine; –R, amine → substituted imine (Schiff's base); –OH, hydroxylamine → oxime; –NH₂, hydrazine → hydrazone; –NHC₆H₅, phenylhydrazine → phenylhydrazone; –NHCONH₂, semicarbazide → semicarbazone; 2,4-dinitrophenylhydrazine → 2,4-dinitrophenylhydrazone.
With 2,4-DNP an aldehyde or ketone gives a coloured solid (yellow, orange or red), which chemists use to identify it.
Semicarbazide has two –NH₂ groups, but only the one joined to the other nitrogen forms semicarbazones; the –NH₂ next to C=O has its lone pair shared with the carbonyl by resonance.
NaBH₄, LiAlH₄ or catalytic hydrogenation reduce aldehydes to primary alcohols and ketones to secondary alcohols (Unit 7).
Clemmensen reduction: zinc amalgam and concentrated hydrochloric acid turn C=O into CH₂.
Wolff-Kishner reduction: the hydrazone formed with hydrazine is heated with sodium or potassium hydroxide in a high-boiling solvent such as ethylene glycol, and C=O again becomes CH₂.