Thermal Properties of Matter

Physics · Class 11

Lesson 13 of 13 · 19 min

Chapter review

Loading the full lesson

Must-know facts

21 facts

  1. 1Heat is energy moving because of a temperature difference; unit joule.
  2. 2Ice and steam points: 0 °C / 100 °C and 32 °F / 212 °F; t_F = (9/5)t_C + 32.
  3. 3PV = μRT with R = 8.31 J mol⁻¹ K⁻¹; absolute zero is −273.15 °C.
  4. 4T = t_C + 273.15; a kelvin and a degree Celsius are the same size.
  5. 5Δl/l = α_l ΔT; area coefficient 2α_l; α_V = 3α_l.
  6. 6For an ideal gas at constant pressure α_V = 1/T (3.7 × 10⁻³ K⁻¹ at 0 °C).
  7. 7Water contracts on heating from 0 °C to 4 °C; it is densest at 4 °C, so lakes freeze from the top.
  8. 8Thermal stress in a clamped rod = YαΔT.
  9. 9Q = msΔT; water's s = 4186 J kg⁻¹ K⁻¹, the largest in the table.
  10. 10C_p > C_v for a gas; molar heat capacity is per mole.
  11. 11Calorimetry: heat lost = heat gained in an isolated system.
  12. 12Temperature stays fixed during melting and boiling; Q = mL.
  13. 13Water: L_f = 3.33 × 10⁵ J kg⁻¹, L_v = 22.6 × 10⁵ J kg⁻¹.
  14. 14Higher pressure lowers ice's melting point (regelation) and raises water's boiling point (pressure cooker).
  15. 15Triple point of water: 273.16 K, where solid, liquid and vapour coexist.
  16. 16H = KAΔT/L; the same heat current crosses every rod in series.
  17. 17Convection needs a fluid; sea breeze by day, land breeze by night.
  18. 18Wien: λ_m T = 2.9 × 10⁻³ m K.
  19. 19Stefan: H = AeσT⁴, σ = 5.67 × 10⁻⁸ W m⁻² K⁻⁴, T in kelvin.
  20. 20Good absorbers are good emitters; a thermos flask cuts all three modes of transfer.
  21. 21Newton's cooling: rate ∝ (T₂ − T₁); ln(T₂ − T₁) against t is a falling straight line.

Common traps

Where marks are lost

Converting a temperature difference with the +273 or +32 offset.

A difference of 1 °C is 1 K and 1.8 °F; offsets apply only to readings, not to differences.

Taking water's maximum density at 0 °C.

It is largest at 4 °C; water contracts on heating from 0 °C to 4 °C.

Using α_l in place of α_V (or 2α_l for volume).

Area uses 2α_l and volume 3α_l for an isotropic solid.

Assuming all the ice melts in a mixture problem.

First compare the heat the warm water can give up to 0 °C with m L_f; if it is smaller, the mixture stays at 0 °C with some ice left.

Using Q = msΔT during melting or boiling.

Temperature does not change during a change of state; use Q = mL for that stage.

Putting °C into Stefan's law.

T⁴ needs absolute temperature in kelvin.

Adding conductivities for rods in series.

The heat current is the same in each rod; equate KAΔT/L across them (equal lengths give K′ = 2K₁K₂/(K₁ + K₂)).

Saying convection can happen in solids.

Convection needs matter to flow; it occurs only in liquids and gases.

Thinking Wien's law gives a star's interior temperature.

It gives the temperature of the emitting surface.

Using the starting temperature in Newton's law over an interval.

Use the average temperature over the interval minus the surroundings' temperature.

Formulas

15 to know

Celsius and Fahrenheit

(t_F − 32)/180 = t_C/100; t_F = (9/5)t_C + 32

Equal at −40.

Kelvin

T = t_C + 273.15

Same unit size as °C.

Ideal-gas equation

PV = μRT

R = 8.31 J mol⁻¹ K⁻¹.

Linear expansion

Δl/l = α_l ΔT

Area: 2α_l; volume: α_V = 3α_l.

Volume expansion

ΔV/V = α_V ΔT

Ideal gas at constant P: α_V = 1/T.

Thermal stress

stress = Y α ΔT; F = Y A α ΔT

Rod held between fixed ends.

Heat capacity

S = ΔQ/ΔT; s = (1/m) ΔQ/ΔT; C = (1/μ) ΔQ/ΔT

J K⁻¹, J kg⁻¹ K⁻¹, J mol⁻¹ K⁻¹.

Heat for a temperature change

Q = m s ΔT

No change of state.

Calorimetry

heat lost = heat gained

Isolated system.

Latent heat

Q = m L

Water: L_f = 3.33 × 10⁵, L_v = 22.6 × 10⁵ J kg⁻¹.

Conduction

H = K A (T_C − T_D)/L

Steady state.

Rods in series

K′ = 2K₁K₂/(K₁ + K₂) (equal lengths)

Same heat current through each rod.

Wien's displacement law

λ_m T = 2.9 × 10⁻³ m K

Hotter body, shorter peak wavelength.

Stefan–Boltzmann law

H = A e σ T⁴; net H = e σ A (T⁴ − T_s⁴)

σ = 5.67 × 10⁻⁸ W m⁻² K⁻⁴; T in kelvin.

Newton's law of cooling

−dQ/dt = k(T₂ − T₁); T₂ = T₁ + C′e^(−Kt)

K = k/(ms); small temperature differences.

Key terms

16 terms

Heat
Energy transferred between bodies because of a temperature difference.
Temperature
A number that measures how hot or cold a body is.
Absolute zero
−273.15 °C, the zero of the Kelvin scale, found by extending gas-thermometer lines to P = 0.
Coefficient of linear expansion
Fractional increase in length per kelvin rise, α_l = Δl/(l ΔT).
Anomalous expansion
Water's contraction on heating between 0 °C and 4 °C.
Thermal stress
Stress set up when a body is prevented from expanding or contracting.
Specific heat capacity
Heat needed per unit mass per unit temperature rise.
Calorimeter
An insulated metal vessel with stirrer used to measure heat exchanged.
Regelation
Melting under pressure and refreezing when the pressure is removed.
Sublimation
Direct change between solid and vapour without passing through the liquid state.
Triple point
The one temperature and pressure at which solid, liquid and vapour coexist.
Latent heat
Heat per unit mass absorbed or released during a change of state at constant temperature.
Thermal conductivity
K in H = KAΔT/L; how readily a material conducts heat.
Convection
Heat transfer by the bulk movement of a fluid.
Emissivity
The fraction of a perfect radiator's emission that a surface emits, between 0 and 1.
Blackbody
An ideal body that absorbs all radiation falling on it and emits the maximum possible radiation at its temperature.
Test yourself: 10 questionsExam-style questions on Thermal Properties of Matter, with full solutions.Start
Chapter review | Thermal Properties of Matter | Lumi Learn