Lesson 6 of 10 · 7 min
Point-slope and two-point forms
NCERT §9.3.1, §9.3.2, §9.3.3
Riya has two points of the canal and its slope. How does she turn that into one equation that every point of the canal obeys?
The lesson in notes
In short
The equation of a line is a condition on (x, y) that is true for every point on the line and false for every point off it.
A horizontal line at distance a from the x-axis is y = a or y = −a; a vertical line at distance b from the y-axis is x = b or x = −b. Through (−2, 3) the horizontal line is y = 3 and the vertical line is x = −2.
Point-slope form: if a line has slope m and passes through (x₀, y₀), its equation is y − y₀ = m(x − x₀). With slope −4 through (−2, 3) this reads y − 3 = −4(x + 2); expanding, y − 3 = −4x − 8, so 4x + y + 5 = 0.
Two-point form: the line through (x₁, y₁) and (x₂, y₂) is y − y₁ = ((y₂ − y₁)/(x₂ − x₁))(x − x₁), which says the slope from P₁ to any point P equals the slope P₁P₂.
Through (1, −1) and (3, 5): the slope is 6/2 = 3, so y + 1 = 3(x − 1), or −3x + y + 4 = 0, which is y = 3x − 4.
Lines are concurrent when they pass through one common point. The lines 2x + y − 3 = 0 and 3x − y − 2 = 0 meet at (1, 1); the line 5x + ky − 3 = 0 passes through (1, 1) when 5 + k − 3 = 0, that is k = −2.