Lesson 8 of 12 · 7 min
Latus rectum of an ellipse
NCERT §10.5.4
Meera wants a straight watering pipe through one peg, square to the long axis, reaching the edge of the oval at both ends. How long must it be?
The lesson in notes
In short
A latus rectum of an ellipse is a chord through a focus perpendicular to the major axis, with its ends on the ellipse. An ellipse has two of them, one through each focus.
Its upper end A = (c, l) = (ae, l) lies on x²/a² + y²/b² = 1, so l² = b²(1 − e²). Since 1 − e² = b²/a², l = b²/a, and by symmetry the full latus rectum is 2b²/a.
For x²/25 + y²/9 = 1 the latus rectum is 2 × 9/5 = 18/5.
Equation from vertices (±13, 0) and foci (±5, 0): a = 13, c = 5, b² = 169 − 25 = 144, giving x²/169 + y²/144 = 1.
Equation from a major axis of length 20 and foci (0, ±5): the major axis is the y-axis, a = 10, b² = 100 − 25 = 75, giving x²/75 + y²/100 = 1.
Equation from two points: if the major axis is along the x-axis and the ellipse passes through (4, 3) and (−1, 4), then 16/a² + 9/b² = 1 and 1/a² + 16/b² = 1. Solving gives a² = 247/7 and b² = 247/15, so 7x² + 15y² = 247.