Complex Numbers and Quadratic Equations

Maths · Class 11

Lesson 9 of 12 · 7 min

Modulus and conjugate

NCERT §4.4

The base station needs two numbers about the rover at 3 + 4i: how far away it is, and where its reflection in the east-west line would be. These are its modulus and its conjugate.

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In short

The modulus of z = a + ib is the non-negative real number |z| = √(a² + b²). For example |3 + 4i| = √25 = 5, |−5 + 12i| = 13 and |2 − 5i| = √29.

The conjugate of z = a + ib is z̄ = a − ib: only the sign of the imaginary part changes. So the conjugate of 3 + 4i is 3 − 4i, of −2 − 7i is −2 + 7i, of 6i is −6i, and a real number is its own conjugate.

z × z̄ = a² + b² = |z|². Hence for z ≠ 0 the inverse is z⁻¹ = z̄/|z|², which is the conjugate trick used in division.

Modulus rules: |z₁z₂| = |z₁||z₂| and |z₁/z₂| = |z₁|/|z₂| when z₂ ≠ 0. For example |(3 + 4i)(5 − 12i)| = 5 × 13 = 65, without multiplying out; the product is 63 − 16i and √(63² + 16²) = √4225 = 65.

Conjugate rules: the conjugate of z₁z₂ is z̄₁z̄₂, of z₁ ± z₂ is z̄₁ ± z̄₂, and of z₁/z₂ is z̄₁/z̄₂ when z₂ ≠ 0.

Also z + z̄ = 2 Re z and z − z̄ = 2i Im z, so z is real exactly when z = z̄.

Worked example: (1 + 7i)/(2 − i) = (1 + 7i)(2 + i)/5 = (2 + i + 14i − 7)/5 = (−5 + 15i)/5 = −1 + 3i, so its conjugate is −1 − 3i.

Modulus and conjugate | Complex Numbers and Quadratic Equations | Lumi Learn