Lesson 8 of 13 · 10 min
SN1 and reactivity order
NCERT §6.7.1
Kavya repeats the test with tert-butyl bromide. Doubling [OH⁻] changes nothing: the reaction runs at the same rate. A different mechanism is at work.
The lesson in notes
In short
SN1 (substitution nucleophilic unimolecular) reactions are usually run in polar protic solvents such as water, alcohol or acetic acid.
(CH₃)₃CBr + OH⁻ → (CH₃)₃COH + Br⁻ follows first order kinetics: the rate depends on [tert-butyl bromide] only, not on [OH⁻].
Step I: the polarised C–Br bond breaks slowly and reversibly into a carbocation and Br⁻; the energy comes from solvation of the halide ion by the protons of the protic solvent. Step II: the nucleophile attacks the carbocation quickly. The slow step sets the rate.
The more stable the carbocation, the faster it forms and the faster the reaction. Tertiary carbocations are the most stable, so 3° halides react fastest: SN1 order 3° > 2° > 1° > CH₃X, the reverse of SN2.
Allylic and benzylic halides are very reactive in SN1 because their carbocations are stabilised by resonance.
For a given alkyl group, both mechanisms follow R–I > R–Br > R–Cl >> R–F; the large iodide ion leaves most readily.
Bromobutanes: SN1 order n-C₄H₉Br < (CH₃)₂CHCH₂Br < CH₃CH₂CH(Br)CH₃ < (CH₃)₃CBr, and SN2 the exact reverse. Of the two primary bromides, (CH₃)₂CHCH₂Br is faster in SN1 because (CH₃)₂CH– has a larger electron-donating inductive effect.
Benzylic bromides: SN1 order C₆H₅C(CH₃)(C₆H₅)Br > C₆H₅CH(C₆H₅)Br > C₆H₅CH(CH₃)Br > C₆H₅CH₂Br, and SN2 the reverse. Two phenyl groups stabilise a cation by resonance, but a phenyl group is bulkier than methyl, which slows SN2.
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SN1 steps and carbocation stability
Magnet Brains · Hinglish · Lecture · Open on YouTube